Convergence and Divergence: The Return of Sequences and Series
We learned a little bit about sequences and series earlier in the mathematics course, but now its time to work with these some more, now that we understand calculus! First up, what does it mean for a sequence or series to be convergent or divergent, and how can we tell which one it is? Let's find out!
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Your voice is so clear and stress-relievingly good to hear.
Professor Dave I just came across your video and I want to express my appreciation at the very clear presentation of the concepts; not only are the slides very clear, you speak with a certain clarity which is rare to come by in a mathematics tutorial. Thank you .
Just the type of explanation I was looking for. Perfectly explained.
This man can explain a 3 month university subject in 10 Minutes
PROFESSOR you explained it so beautifully. Thanks.
Thank you for giving that example! I would love to see some more as you continue to do these videos
I had a problem all during my semester in this concept.. but now it's so clear ! I can't thank u more man :)
@@jonathanlimjun6238 what do you know about convergence
Thanks for the video. This has made me understand a lot of things I have been missing. Good work!
Thanks professor Daves. This video really helped me in understanding the basics of convergent and divergent series. And , I would also like to place a demand for a video on Maclaurain's series.
I did that too, check the mathematics playlist!
Thankyou sir for such a simplified explanation.
Great video! your explanation is very easy to understand
Very good explanation. Thank you so much for all your nice demonstration.
Thank you for this video, it has lifted up some uncertainties.
thanks, man!! really clear and useful, and also insightful; ❤️❤️
Thanks for the knowledge you have shared with me.
you gotta do more of these man
at 8:50 why that sum will be divergent ? i thought it will converge to 1/5?
same here
thank you very much sir....this concept is clear to me now
It was a good revision! Great job 👏
Very clear explanation, thanks!
Perfectly explainedd🔥
Crystal clear! Thank you!
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GREAT WORK KEEP UP!
Great explanation !
Omg, thank you so much. This video really helped bridge the gap between all this information and how it works together. Before, it was like a jumbled mess in my head.
@@jonathanlimjun6238 yeah, professor Dave is really great at explaining topics in a much more coherent and intuitive way
Thanks so much 🙏🏼🙏🏼🙏🏼I have understood a lot 😊
Excellent explanation
Thaaaaanks a lot🙏Finally,I understood!
Thanks loved it.
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Thank you so much!!!
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Like your animations
great lecture! Thank you professor a lot!
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Very very helpful!!!!! Thanks!!!!!!
Thank you 🙏🙏🙏
THANK YOU SO MUCH
This helped me with my Alevel
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How can math be amazing like this 😍
Then series diverge when they sum constants and ever increasing values and converge when they sum ever decreasing values? really simple and good explanation!
This professor is good. I like this video
Thank you Lord Farquad you are the best!
Thank you 😊👍 so much from India.
so helpful
Thank.You Professor
"let's converge a little"
Good one
converge me daddy UwU
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Thank you
Pro Dave u are the best........................!!!!!!!!!!!!!
(6:35): for r=-1, the terms are a,-a, a,-a, a,-a… .
0:50 bold of you to assume that 😅
He knows a lot about all kinds of stuff
thanks sir
Is it possible for a sequence with two different numbers to converge?
thank you
great man
Hey Dave. Would you consider following up this course with a linear algebra course? All the best, Bram
don't worry, linear algebra is coming! i already filmed some of it.
Professor Dave Explains Hugs!
When the limit of a sequence is zero then the corresponding series will be convergent and when the limit of a sequence gives some constant value L then the sequence is convergent. Is this right? Please correct me.
Ty for making me understand bro
Sir , limit of1/n is zero still series is divergent this theorem goes wrong in this case is it exception ??????? Pls reply sir
1:16 This seems like a divergent series but actually is convergent. There are some simple and complex proofs to show that 1+2+3+.....= -1/12. This is same as Riemann zeta function for -1.
so if the resulting series is zero it is convergent?
whats the name of the theorem at 7:17?
Hi prof Dave .do you have videos about Taylor and Mclaurin series.Thank you.
Yep!
love from India
Hey can a convergent sequence have an answer which is a complex number...as n approaches infinity
hmm yes i believe so, at least definitely if there are complex numbers in the sequence!
7:05 how to get that answer?
This Math Is Worse Than Programming.... My Head Is About To Explode
Hey professor Dave, what else after calculus in this course
linear algebra! and then hopefully differential equations.
thanks they're really helpful
I don't get it because at the beginning he said that if it gets to a finite number it is convergent and in the end when he gets1/5 he said it is divergent ;-; please somebody help me
Pirates if they give up Piracy and go to the Caribbean University 6:05
🙏🏻 🙏🏻 🙏🏻
which playlist is this video in?????
math
2:54 the sequences should start from 1
nice
I lost it at "In fact,..." 7:10 😪
I needed help on precalc 20 and it started talking about integrals and limits 😥😥
i have a tutorial earlier in my mathematics playlist on sequences and series, that's probably the one you're looking for. just go to the long playlist, it's somewhere in the 80s i think.
I confused how lim of 1/2^n = 1 . I thought it should be 0. becz 1/inf = 0.
he just said in the video clearly that if a sequence converges to 0 as it approaches its infinite-th term, the series that the sequence generates would have a finite number limite. i think u're mixing up sequence and series, which is the first thing he stated in the video
2:17 Why Am I laughing so hard
🙏
❤
If you are going to reference previous tutorials, a link in the comments would be good.
just go to my mathematics playlist, also i usually link using cards in the top right
First equation = -1/12 ;)
来自华东地区某211高校,看完这个视频才知道国内高数老师是什么东西😅
4:37 .1+2+3+....=-1/12 ...ramanujuan....
It is a special case for a special type of function. You will get zero no. If you write this in your exam
Only using analytic continuation on a different function (continued riemman zeta function) that is closely related to but not interchangeable with that sum. The function that gives you that sum (riemman zeta function) only works for inputs with a real part greatrr than one. The RZ function breaks when you get smaller than one. But if you "continue" the riemman zeta function throughout the complex plane (ensuring it is analytically continued), when you plug in (-1), which using the non-continued riemman zeta function (∑«n=1→∞» (1/n^s) for varying values of s) would blow up to infinity, you get (-1/12). So there is a sense in which the sum you get from the non continued RZ function, 1+2+3+4... also equals (-1/12).
Simple af
I'm here from FLVS (Florida Virtual School) and I would like to say Big Chungus Funny.
1+2+3+4+5+……= -1/12 😢
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Sir still I haven't got a reply. Waiting for your explanation. Creating a youtube clip for those questions will be realy helpful. Waiting for your email
wasn't it -1/12
The sum of all *n* natural numbers is a diverging series coz it doesn't approach any sensible value , try substituting as n→∞ in the formula n(n+1)/2 , -1/12 isn't the true sum coz this result can't be verified using the convergence and divergence test!
@@wolframalpha8634 the result can't be found as addition doesn't happen assuming a linear number line (well I know line is linear , dunno how else to put it in words) . And also he did put n as infinite and write sum as infinite so.... Btw thx
@@gautamchettiar4150 uhmm.. I didn't understand about addition on a linear number line?
@@wolframalpha8634 you can understand it on 3b1b channel's video
@@gautamchettiar4150 thanks! I'll watch it
best
convergent = limit does not exist
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Jujutsu kaisen brought me here
this video has false information,a limit of a sequence can exist and be equal to a real number and the sequence can diverge.
if a sequence converges at some finite number, it's convergent. that's what "converge" means. a divergent sequence goes to infinity, by definition.
Its wrong, as the series n^2/(5n^2+4) would be a convergent series.......please don't try to teach till you are not fully clear in your concept
It's a convergent sequence, but it does not converge to zero, so the series that is the sum of the terms of the corresponding sequence will be divergent. Please don't try to make presumptuous comments until you are fully clear on the concepts.
You should first understand the relation between a SEQUENCE and a SERIES before making presumptuous comments...