10 Ways You Can Use "_" In Python (Do you know ALL of them?)

2024 ж. 13 Мам.
21 464 Рет қаралды

Here are 10 ways you can use the underscore (_) in Python when programming. Did you know all of them?
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00:00 Intro
00:05 1) Last used value
00:49 2) Number formatting
01:27 3) Unimportant values
02:17 4) Unimportant exceptions
02:56 5) Unpacking
03:37 6) Super unpacking
04:16 7) Protected
05:46 8) Private
06:41 9) Reserved names
07:17 10) Dunder methods
09:26 11) Naming variables
09:34 Conclusion

Пікірлер
  • "as _" ? Why the h*** would you ever do that? Just delete those 4 extra characters from you code

    @aflous@aflous Жыл бұрын
    • it's used by django's translate engine

      @thegothaur@thegothaur2 ай бұрын
  • My Mom: What should we name him? My Dad: Name him "_", we do not care about him

    @ilcp331@ilcp33111 ай бұрын
    • In C# it is literally called the discard character

      @shreyasj6437@shreyasj64372 ай бұрын
  • In try except if you need to use _ you don't need it in the first place, just try except without variable output. Otherwise, great video man, this one was useful and informative 👍🏻

    @Sinke_100@Sinke_100 Жыл бұрын
  • 2:32 But if you don't need to use the exception, why even write "as _" instead of leaving it to be "except ZeroDivisionError:"?

    @callbettersaul@callbettersaul Жыл бұрын
    • From what I read and saw, some people use it to explicitly show that they are ignoring it, but it is probably a very rare use case.

      @Indently@Indently Жыл бұрын
    • @@Indently I am glad I never saw that. I'd be confused. If I explicitly want to ignore an exception, I'd just leave the assignment out. And if I don't even want to handle it, I'd use contextlib.suppress().

      @richardneumann3335@richardneumann33359 ай бұрын
    • ​@@Indently well, if one wants to suppress it, with contextlib.suppress() is a much cleaner option

      @vinylSummer@vinylSummer5 күн бұрын
  • Great presentation style and hugely memorable content! Thanks Buddy.

    @garybigden810@garybigden810 Жыл бұрын
  • You forgot about 'case _:' in a match expression. Example: n = int(input()) match n: case 1: print("n is 1") case 2: print("n is 2 times more than 1") case 3: print("n is bigger than 1") case _: print("n is weird")

    @MetaaR@MetaaR2 ай бұрын
    • Here, _ is a wildcard that never fails to match. If none of the other cases match, it will match with case _.

      @user-iy6dt4xp5o@user-iy6dt4xp5oАй бұрын
  • Thats very good. Looking forward to dunder methods of class video.

    @loverboykimi@loverboykimi Жыл бұрын
  • I enjoy your videos with your personal touch.

    @finnthirud@finnthirud Жыл бұрын
  • I think some of it was refreshing, duunder methods, however there were pretty neat tricks there!! We'll certainly be back again!!

    @t.e.k.profitstraders8796@t.e.k.profitstraders8796Ай бұрын
  • What's the benefit to using it in exception handling, when you don't need to catch what the exception is at all if you're not gonna use it? Am I missing anything?

    @lukerichards1188@lukerichards1188 Жыл бұрын
  • What text editor/IDE you are using

    @gravity9999@gravity9999 Жыл бұрын
  • Unimportant exceptions was a new one for me!

    @murphygreen8484@murphygreen8484 Жыл бұрын
  • Can you cover setting _ (underscore) instead of method parameters in the signature some method/function? Uses cases: the IDE or linter complains the parameter is not used, but you don't need it and the specification states you must put it there, and also it doesn't support optional params and other neat features and it's in args section so no kwargs will work.

    @DamjanDimitrioski@DamjanDimitrioskiАй бұрын
  • How can we connect Cypress to python in pycharm? Can you please tell me

    @DealazonDaily@DealazonDaily Жыл бұрын
  • Some are pretty useful.

    @mayorc@mayorc Жыл бұрын
  • Wonderfull!

    @luissantos975@luissantos975 Жыл бұрын
  • To point 4, it is also default case in the new match structure (3.10 and up). match type(myvariable): case type(int()): do_int_staff(myvariable) case type(float()): do_float_stuff(myvariable) case type(str()): do_string_stuff(myvariable) case _: print(f"Unsupported type {_}") Update: someone explains to me why this code throws an error in line case type(int()) but print(type(int())) works as expected.

    @oida10000@oida1000010 ай бұрын
    • match case is pattern matching, you're using type(int()) you should just use int()

      @thomaseb97@thomaseb9710 ай бұрын
    • Is that not just a naming convention? Doing `case unused_variable:` would do the same thing

      @schlopping@schlopping9 ай бұрын
    • just case int: doesn't work..?

      @sangchoo1201@sangchoo12019 ай бұрын
    • @@sangchoo1201 case int: would compare it to literally the int type, instead of checking if its an instance of int or not. its supposed to be case int():

      @schlopping@schlopping9 ай бұрын
    • @schloppppdev3002 1. match type(myvariable): wants to check the variable's type 2. match int(): is actually checking the variable matchs 0 (because default constructor of int creates 0)

      @sangchoo1201@sangchoo12019 ай бұрын
  • 6:48 a more common reserved name that would be wanted to use it for something else is "id" , it let's you reassign it though, but it's not recommended .

    @intron9@intron92 ай бұрын
  • For 7 (Private) and 8 (Protected) - 4:16-6:40, I believe you are mistaken. AFAIK, both protected and private methods use a single underscore by convention, and name mangling with double underscore is not correct. Though both are common, I believe name mangling is incorrect. I don't know how to verify this, though.

    @HorridModz@HorridModz Жыл бұрын
    • I don't know where you're getting your information from. What I shared is a very common convention in Python, if you want to learn more about name mangling, check out mCoding, he made a proper video on it. Otherwise if you have resources that prove otherwise, I wouldn't mind looking at them.

      @Indently@Indently Жыл бұрын
    • @@Indently The name mangling is to avoid subclasses accidentally overriding parent class methods when inheriting. This behavior is documented in the wiki (and pep-0008): "Python's runtime does not restrict access to such attributes, the mangling only prevents name collisions if a derived class defines an attribute with the same name."

      @user-vt9bp2ei1w@user-vt9bp2ei1w11 ай бұрын
    • ​@@user-vt9bp2ei1w Yes I agree, the function does not become private neither it becomes difficult to find its name. I tried this by creating a sample class with a double underscore leading function. Then I passed in the object created by that function in dir() global function which had the function inside my class named as: '_ClassName__functionName'. According to PEP 8 : __double_leading_underscore: when naming a class attribute, invokes name mangling (inside class FooBar, __boo becomes _FooBar__boo)

      @ommahajan1@ommahajan111 ай бұрын
  • Thanks

    @rishiraj2548@rishiraj2548 Жыл бұрын
  • what IDE do you use??

    @samadshaik@samadshaik11 ай бұрын
    • it's pycharm

      @sangchoo1201@sangchoo12019 ай бұрын
  • _ is just a variable name. with a context of "I don't use it"

    @sangchoo1201@sangchoo12019 ай бұрын
    • Not exactly. open python console, type '10', enter. Then type '_' , enter. you'll see 10. More than "just a variable name"

      @eitantal726@eitantal7262 ай бұрын
    • @@eitantal726 but it's still just a variable name, although the referenced variable is a special variable

      @sangchoo1201@sangchoo12012 ай бұрын
    • @@sangchoo1201 no, "Eitan" is just a variable name. when I type 10 and Eitan, I don't see 10. _ is different. I see it as "ANS" of the calculator

      @eitantal726@eitantal7262 ай бұрын
    • @@eitantal726 but _ IS a variable name, isn't it? what is a variable name: sangchoo1201 _ input what is NOT a variable name: if @#$ 1a

      @sangchoo1201@sangchoo12012 ай бұрын
  • U could do user._User__get_id() at 6:35 if any1 was curious

    @daggerhound1395@daggerhound1395 Жыл бұрын
  • I’ve come across both * and _ in an unpacking context, but never *_ together. Is that quite new?

    @gavintillman1884@gavintillman1884 Жыл бұрын
    • It's been around for as long as I can remember :)

      @Indently@Indently Жыл бұрын
    • "*" usually means all so you are unpackaging all the in between values to "_"

      @ali-g@ali-g Жыл бұрын
    • I’m overanalysing it. It’s just treating _ as a variable and doing the usual * unpacking. So *_ isn’t a Python symbol, it’s just the * unpacking operator applied to variable _. The whole _ is just a convention that it’s ignored, syntactically (outside of console mode) it’s just another variable - right?

      @gavintillman1884@gavintillman1884 Жыл бұрын
    • @@gavintillman1884 Yes exactly, if you want you can even use emojis instead of _. "*" operator changes it's behaviour if it's in between int or float data types; acts as a multiplier. If left side is a string and right side is an int, acts as a repeater. I think these two the most common ones.

      @ali-g@ali-g Жыл бұрын
  • Why does this video not mention the important role _ plays is match patterns?

    @alexislayton2150@alexislayton215011 ай бұрын
    • Because I absolutely forgot about it until you mentioned it! damn, it will be for the next one

      @Indently@Indently11 ай бұрын
    • @@Indently you forgot to mention one another common use you are even using in the video, defining __init__ method for classes 7:53 anyway great video as usual!

      @yoverale@yoveraleАй бұрын
  • Basically, underscore is just variable name or simple letter. Nothing special. In can be replaced with any other letter.

    @HononoSNK@HononoSNK8 ай бұрын
  • Why use __str__() instead of __repr__()?

    @lukerichards1188@lukerichards1188 Жыл бұрын
    • __str__ is to convert the instance to a string __repr__ is to represent the state of an instance (more close to debugging stuff)

      @sangchoo1201@sangchoo12019 ай бұрын
  • Everyone asks what is an underscore but no one asks how is the underscore...

    @mhm6421@mhm642111 ай бұрын
    • That is very True

      @Indently@Indently11 ай бұрын
  • Update you IDE

    @aimanshaa@aimanshaa Жыл бұрын
    • Update you grammar

      @kaninchengaming-inactive-6529@kaninchengaming-inactive-6529 Жыл бұрын
    • @@kaninchengaming-inactive-6529 but you used the same bad grammar as he did

      @qwerty_qwerty@qwerty_qwerty11 ай бұрын
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